If it's not what You are looking for type in the equation solver your own equation and let us solve it.
15x^2+4x-320=0
a = 15; b = 4; c = -320;
Δ = b2-4ac
Δ = 42-4·15·(-320)
Δ = 19216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{19216}=\sqrt{16*1201}=\sqrt{16}*\sqrt{1201}=4\sqrt{1201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{1201}}{2*15}=\frac{-4-4\sqrt{1201}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{1201}}{2*15}=\frac{-4+4\sqrt{1201}}{30} $
| 10(d+6)=80 | | 13(9x−18)=2x−3+x−3 | | 5y²+12y=0 | | 35+x=30 | | 4z-15=1 | | 6(-10-y)+40+y=180 | | 36=2x^ | | 15=4b+7 | | -8u+6(u+3)=34 | | 100+x=30 | | 5x+19=x+31 | | 3.5=(2)^n | | (3-2x)(x+2)=5 | | 3.5=2^n | | 3x+6/x+7=3 | | 4.9g+5=1.9g+14 | | 9x-16=x-16 | | x^2/5=81/5 | | 1/4(10x+15)-3/2=2x+6+3x | | 13x+12=x+48 | | -2-3+x=10 | | 4(4x+2)=4(2x+3)+4x | | 81=1-5(-1+5x) | | x+10-8=10 | | (x-5)(x²+3)=0 | | -20+y=100 | | p-3=13 | | p+2=28 | | 2(4x+6)=3x-3 | | m+0=-15 | | 3x^-10=2x | | 2k=6+4 |